A hemispherical tank is made up of an iron sheet 1 cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank.

`["Assume "pi=22/7]`

Advertisement Remove all ads

#### Solution

Inner radius (*r*_{1}) of hemispherical tank = 1 m

Thickness of hemispherical tank = 1 cm = 0.01 m

Outer radius (*r*_{2}) of hemispherical tank = (1 + 0.01) m = 1.01 m

`"Volume of iron used to make such a tank "=2/3pi(r_2^3-r_1^3)`

`=[2/3xx22/7xx{(1.01)^3-(1)^3}]m^3`

`= [44/21xx(1.030301-1)]m^3`

= 0.06348 m^{3} (approximately)

Concept: Volume of a Sphere

Is there an error in this question or solution?

#### APPEARS IN

Advertisement Remove all ads